论文标题
$ z_ {c}（3900）$的磁矩作为轴向矢量分子状态
The magnetic moment of $Z_{c}(3900)$ as an axial-vector molecular state
论文作者
论文摘要
在本文中，我们初步分配$ z_ {c}（3900）$作为轴向向量分子状态，并在外部弱电磁场中使用QCD总规则法计算其磁矩。从外部电磁场中的两点相关函数开始，并以电磁相互作用的力量扩展，我们将$ z_ {C}（3900）$的质量和极残留物从扩展中的领先任期和从线性响应到外部电子电磁场的磁力响应中的磁矩中的领先任期中提取。数值为$ m_ {z_ {z_ {c}} = 3.97 \ pm0.12 \ mbox {gev} $与实验值$ m^{exp} _ {z_ {z_ {c}} = 3899.0 $λ_{z_ {c}} = 2.1 \ pm0.4 \ times10^{ - 2} \ mbox {gev}^{5} $和$μ__{z_ {z_ {c}} = 0.19 = 0.19^{+0.04}^{+0.04}
In this paper, we tentatively assign $Z_{c}(3900)$ to be an axialvector molecular state, and calculate its magnetic moment using the QCD sum rule method in external weak electromagnetic field. Starting with the two-point correlation function in external electromagnetic field and expanding it in power of the electromagnetic interaction Hamiltonian, we extract the mass and pole residue of $Z_{c}(3900)$ state from the leading term in the expansion and the magnetic moment from the linear response to the external electromagnetic field. The numerical values are $m_{Z_{c}}=3.97\pm0.12\mbox{GeV}$ in agreement with the experimental value $m^{exp}_{Z_{c}}=3899.0\pm3.6\pm4.9\mbox{MeV}$, $λ_{Z_{c}}=2.1\pm0.4\times10^{-2}\mbox{GeV}^{5}$ and $μ_{Z_{c}}=0.19^{+0.04}_{-0.01}μ_{N}$.
